Question

The increasing order of base strength of $C{l}^{-},C{H}_{3}COO{,}^{-}O{H}^{-}$ and $F^{-}$ is:

• A. $Cl<F^{-}<C{H}_{3}COO{<}^{-}OH$
• B. $Cl>F^{-}>C{H}_{3}COO{>}^{-}OH$
• C. $C{H}_{3}COO<Cl<F^{-}{<}^{-}OH$
• D. none of these

Answer 1

Answer: (A)

$Cl<F^{-}<C{H}_{3}COO{<}^{-}OH$

$\left(A\right)$ $C{l}^{-}$<$F^{-}$<$C{H}_{3}CO{O}^{-}$<$O{H}^{-}$

$Reason$: Hydroxide is a much stronger base. It is less electronegative and there is a hydrogen atom bonded to it, giving it some electron density.