The increasing order of basicity of the following compounds is:

(d)<(b)<(a)<(c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a)<(b)<(c)<(d)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b)<(a)<(c)<(d)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b)<(a)<(d)<(c)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D (b)<(a)<(d)<(c)
Here, (c) is the most basic because its conjugate acid is stabilized by equivalent resonance. Out of (a) and (d), (d) is more basic due to +I effect. (b) is less basic than (a) and (d) because the $N$ atom is $s p^{2}$ hybridised.

Suggest Corrections

Similar questions

The order of the increasing basicity of the compounds is as follows.

C H_{3} N H_{2}, (C H_{3})_{2} N H, N H_{3}, C_{6} H_{5} N H_{2}

(A)

C H_{3} C H_{2} N H_{2}

(B)

C H_{3} C H_{2} C H_{2} C H_{3} | N H

(C)

H_{3} C - C H_{3} | N - C H_{3}

(D)

P h - C H_{3} | N - H

Join BYJU'S Learning Program