The increasing order of bond dissociation enthalpy of the following substances is:

$F_{2} < C l_{2} < B r_{2} < I_{2}$

If the order of bond dissociation enthalpy is true enter 1 else 0.

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Solution

With an increase in size, the bond dissociation enthalpy decreases. Fluorine has exceptionally low bond dissociation enthalpy because of the high electronegativity but higher than iodine.

So the increasing order of bond dissociation enthalpies is $C l_{2} > B r_{2} > F_{2} > I_{2}$

So the correct answer is 0.

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