The increasing order of effusion among the gases, $H_{2}, O_{2}, {N H}_{3}, {C O}_{2}$ is:

H_{2}, {C O}_{2}, {N H}_{3}, O_{2}

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H_{2}, {N H}_{3}, O_{2}, {C O}_{2}

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H_{2}, O_{2}, {N H}_{3}, {C O}_{2}

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{C O}_{2}, O_{2}, {N H}_{3}, H_{2}

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Solution

The correct option is D ${C O}_{2}, O_{2}, {N H}_{3}, H_{2}$
According to Graham's law, rate of effusion $(r)$ is inversely proportional to the square root of molecular mass $(M)$ of the gas, i.e.,

$r \propto \frac{1}{\sqrt{M}}$

Now,
Molecular mass of $H_{2} = 2 g$
Molecular mass of $O_{2} = 32 g$
Molecular mass of $N H_{3} = 17 g$
Molecular mass of $C O_{2} = 44 g$

Hence the increasing order of rate of effusion among the given gases is-
$C O_{2} < O_{2} < N H_{3} < H_{2}$

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