You visited us 1 times! Enjoying our articles? Unlock Full Access!

Multi-Electron Configurations and Orbital Diagrams

The increasin...

Question

The increasing order of electron affinity of the electronic configurations of element is:
(I) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$
(II) $1 s^{2} 2 s^{2} 2 p^{3}$
(III) $1 s^{2} 2 s^{2} 2 p^{5}$
(IV) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$

I > I V > I I I > I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I > I V > I I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I > I V > I I > I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I V > I > I I I > I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I I I > I V > I I > I$
The affinity of electron depends on the outer shell configuration of an element.
From given configurations, $I I I$ will have highest electron affinity as $2 p$ is more closer to the nucleus and it is deficient of $1$ electron to complete its octet. This will be followed by $I V$ where $3 s$ orbital requires $1$ electron. $I I$ will have less electron affinity than $I V$ because half-filled $p$ orbital is stable. $I$ will have the least electron affinity as $3 p$ is comparatively farther from nucleus. Hence, the required order is:
$I I I > I V > I I > I$

Suggest Corrections

Similar questions

Arrange the elements with the following electronic configurations in the increasing order of electron affinity

(i) $1 s^{2} 2 s^{2} 2 p^{3}$ (ii) $1 s^{2} 2 s^{2} 2 p^{4}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

H C N

H C H O

C H_{3} C O C H_{3}

P h C O C H_{3}

P h C O P h

+ I

- C H_{3}

- C D_{3}

- C T_{3}

- C H D_{2}

C e^{3 +}

L a^{3 +}

P m^{3 +}

Y b^{3 +}

P h O^{⊖}

C H_{3} S^{⊖}

⊖ O H

M e O^{⊖}

Join BYJU'S Learning Program