The increasing order of paramagnetism of : (I) MnSO4.4H2O (II) FeSO4.7H2O (III) NiSO4.6H2O (IV) CuSO4.5H2O
A
I < II < III < IV
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B
IV < III < II < I
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C
III < IV < II < I
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D
III < IV < I < II
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Solution
The correct option is A I < II < III < IV Mn2+ n = 5 ; Fe2+ n = 4 ; Ni2+ n = 2 and $Cu^{2}+ n = 1n = number of unpaired electron and n α paramagnetism.