The increment cost curves of three generators are shown, the demand on the system is 240 MW.
For economic load dispatch the generators schedule is
A
P1=20MW,P2=70MW,P3=150MW
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B
P1=20MW,P2=150MW,P3=70MW
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C
P1=50MW,P2=50MW,P3=90MW
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D
P1=20MW,P2=90MW,P3=130MW
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Solution
The correct option is AP1=20MW,P2=70MW,P3=150MW G1 is high cost generator, so it will supply minimum power, P2+P3=220MW,P1=20MW
From the curve,(IC2−10)=0.1(P2−50) ⇒IC2=0.1×P2+5
For economic dispatch IC2=IC3 0.1×P2+5=12 ⇒P2=70MW P3=150MW