Question

The inductance of a choke-coil is $0.2$ henry and its resistance is $0.50\Omega$. If a current of $2.0$ ampere (rms value) and frequency $50Hz$ is passed through it, what will be the potential difference across its ends?

• A. $145.6V$
• B. $125.6V$
• C. $135.6V$
• D. $185.6V$

Answer 1

Answer: (B)

$125.6V$

We Know,

$X_L=\omega L=0.2\times 2\pi \times 50=20\pi$ (i.e Inductive reactance)

Here, WE want only $V_{L\left(rms\right)}$

$V_L=X_L\times I$ ( rms value of $V_L$)

$V_L=20\pi \times 2.0=40\pi =40\times 3.14=125.6V$

Hence Option $B$ is the correct answer.

Note: Here we calculate rms voltage because nothing is mentioned

about the time at which the voltage should be calculated.