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B
(b)x={−2,−1,1}
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C
(c)x={−2,1,0}
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D
(d)x={−2,−1,0}
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Solution
The correct option is A (d)x={−2,−1,0} −1≤2x+4<5⇒−1−4≤2x<5−4⇒−5≤2x<1⇒−52≤x<12⇒x can take the values between −212and12⇒ If x is an integer, then x={−2,−1,0}