wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The inequality x2sinx+cos2xex+ln2x<x2|sinx|+cos2xex+ln2x is true for x

A
(π,0)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(0,π2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(π2,π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[2nπ,(2n+1)π] nN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (π,0)
|a+b+c|<|a|+|b|+|c|
The above inequality is valid only if either one of a,b or c has different signs.
here, excos2x and ln2x are both positive,
hence inequality will be valid only iff
x2sinx<0
sinx<0
x(π,0)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon