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The infinite sand slope shown in the figure is one the verge of sliding failure. The ground water table coincides with the ground surface. Unit weight of water γw=9.81kN/m3.

The value of the effective angle of internal friction (in degrees upto one decimal place) of the sand is
  1. 34.33

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Solution

The correct option is A 34.33
F.O.S =Shearstrength(τf)Shearstress(τ)

F.O.S = γsubHcos2βtanϕγsatHcosβsinβ

1 = γsubtanϕγsattanβ

1 = (219.81)tanϕ21tan20

tanϕ=21×tan2011.19

ϕ=34.33

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