The initial capacitance of a parallel plate capacitor is C0 and after introducing a conducting sheet of thickness d3, the capacitance becomes C. Then CC0 is
A
23
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B
32
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C
34
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D
43
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Solution
The correct option is B32 Capacitance without dielectric is given by
C0=ϵ0Ad
As we know that capacitance of partially filled dielectric slab of thickness t and dielectric constant K is given by
C=ϵ0Ad−t+tK
Given:
Thickness of dielectric, t=d3
Dielectric constant of a conductor,K=∞
Hence, new capacitance will be,
C=ϵ0Ad−t+tK=ϵ0Ad−d3+d3×∞
⇒C=3ϵ0A2d=32C0
∴CC0=32
Hence, option (b) is correct.
Key concept- Dielectric constant of a metal is infinite.