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Faraday's Second Law

The initial c...

Question

The initial charge across capacitors A and B are shown with Q =CE. Find the ratio of final charge in capacitor A to the final charge in capacitor B, when cells are switched on.___

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Solution

$2 E - \frac{θ_{A}}{C} - \frac{θ_{B}}{C} = 0 E - \frac{θ_{B}}{C} = 0 θ_{A} = C E θ_{B} = C E \frac{θ_{A}}{θ_{B}} = 1$

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