Question

The initial level of water in a measuring cylinder was $12ml$. When an iron piece of irregular shape is completely immersed, the water level changed to $30ml$. Find the volume of iron in $m^3$.

• A. 1.8$\times$${10}^{-6}$$m^3$
• B. 18$\times$${10}^{-6}$$m^3$
• C. 18$\times$${10}^{-6}$$c{m}^3$
• D. 18$\times$${10}^{-6}$$m^3$

Answer 1

The correct option is B

18$\times$${10}^{-6}$$m^3$

Initial level of water, $V_1=12ml$
Final level of water, $V_2=30ml$
Volume of iron piece $V=V_2$- $V_1$
= $30-12=18ml$
Since $1ml=1c{m}^3$, $V=18c{m}^3$
Also $1c{m}^3$ = ${10}^{-6}$$m^3$
Volume of iron piece = $18\times$${10}^{-6}$$m^3$