Question

The initial level of water in a measuring cylinder was $12\text{ml}$. When an iron piece of irregular shape is completely immersed, the water level increased to $30\text{ml}$. What is the volume of the iron piece?

• A. $18\times {10}^{-3}{\text{m}}^3$
• B. $18\times {10}^{-6}{\text{m}}^3$
• C. $18\times {10}^{-6}{\text{cm}}^3$
• D. $18\times {10}^{-4}{\text{m}}^3$

Answer 1

The correct option is B $18\times {10}^{-6}{\text{m}}^3$

The initial level of water, ${\text{V}}_1=12\text{ml}$
The final level of water, ${\text{V}}_2=30\text{ml}$

Hence, the volume of the iron piece:

$\text{V}={\text{V}}_2-{\text{V}}_1$

$\text{V}=30\text{ml}-12\text{ml}=18\text{ml}$

Since $1\text{ml}={10}^{-6}{\text{m}}^3$

$\text{V}=18\times {10}^{-6}{\text{m}}^3$