Question

The initial level of water in a measuring cylinder was $150ml$. When an iron piece of irregular shape is completely immersed, the water level changed to $190ml$. Find the volume of iron.

• A. $4\times {10}^{-6}{m}^3$
• B. $40\times {10}^{-6}{m}^3$
• C. $400\times {10}^{-6}{m}^3$
• D. $4000\times {10}^{-6}{m}^3$

Answer 1

The correct option is B $40\times {10}^{-6}{m}^3$

Given:
Initial level of water, $V_1=150ml$
Final level of water, $V_2=190ml$

The increase in volume is equal to the volume of iron piece. Hence, volume of iron piece is:
$V=V_2-V_1$
$V=190-150=40ml$

From unit conversions, $1ml={10}^{-6}{m}^3$

$⟹V=40\times {10}^{-6}{m}^3$