Question

The initial level of water in a measuring cylinder was 50 ml. When an iron piece of irregular shape is completely immersed, the water level changed to 130ml. Find the volume of iron in $m^3$.

• A. 18$\times$${10}^{-6}$$m^3$
• B. 80$\times$${10}^{-6}$$m^3$
• C. 180$\times$${10}^{-6}$$c{m}^3$
• D. 1800$\times$${10}^{-6}$$m^3$

Answer 1

The correct option is B

80$\times$${10}^{-6}$$m^3$

Initial level of water, $V_1=50ml$
Final level of water, $V_2=130ml$
Volume of iron piece $V=V_2$- $V_1$
= $130-50=80ml$
Since $1ml=1c{m}^3$, $V=80c{m}^3$
Also $1c{m}^3$ = ${10}^{-6}$$m^3$
Volume of iron piece = $80\times$${10}^{-6}$$m^3$