Question

The initial rate of zero-order reaction of the gaseous reaction $A\left(g\right)\to 2B\left(g\right)$ is ${10}^{-2}Mmi{n}^{-1}$. If the initial concentration of A is 0.1 M, then the concentration of B after 60 sec would be:

• A. 0.09 M
• B. 0.01 M
• C. 0.02 M
• D. 0.002 M

Answer 1

The correct option is C 0.02 M

${\left[A\right]}_t$ = ${\left[A\right]}_0$ – $kt$

${\left[A\right]}_t$ = $\left(0.1\right)-\left(\frac{(10{)}^{-2}\times 60}{60}\right)$

${\left[A\right]}_t$ = $0.09$ M

${\left[B\right]}_t$ = $2\times \left(.0.045\right)$

${\left[B\right]}_t$ = $0.09$ M

hence the correct answer is -

(a) $0.09$ M