The initial temperature of half litre of water is 20-C- On supplying heat to it- its temperature rises to 72-C- For every 1-C rise in temperature per gram of water- 4-2 J of heat is needed- Calculate the heat capacity of water-

Given:mass water = half litre i.e., m=500g Δ T=72 20=50 #176;C heat required to raise the temperature of 1 gm of water, Q=4.2Jg^ 1 #176;C^ 1 ...

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Standard X

Physics

Principle of Calorimetry

The initial t...

Question

The initial temperature of half litre of water is $20^{\circ} C$ . On supplying heat to it, its temperature rises to $72^{\circ} C$ . For every $1^{\circ} C$ rise in temperature per gram of water, 4.2 J of heat is needed. Calculate the heat capacity of water.

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Solution

Given:
mass water = half litre i.e., $m = 500 g$
$Δ T = 72 - 20 = 50 ° C$
heat required to raise the temperature of 1 gm of water, $Q = 4.2 J g^{- 1} ° C^{- 1}$
Heat capacity of water=mass of water $\times$ heat required per gram to raise its temperature,
$⟹ = 500 \times 4.2 = 2100 J ° C^{- 1}$

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The initial temperature of half litre of water is 20∘C. On supplying heat to it, its temperature rises to 72∘C. For every 1∘C rise in temperature per gram of water, 4.2 J of heat is needed. Calculate the heat capacity of water.

Given:mass water = half litre i.e., m=500gΔT=72−20=50°Cheat required to raise the temperature of 1 gm of water, Q=4.2Jg−1°C−1Heat capacity of water=mass of water× heat required per gram to raise its temperature, ⟹=500×4.2=2100J°C−1

The initial temperature of half litre of water is $20^{\circ} C$ . On supplying heat to it, its temperature rises to $72^{\circ} C$ . For every $1^{\circ} C$ rise in temperature per gram of water, 4.2 J of heat is needed. Calculate the heat capacity of water.