The initial velocity of a body moving along a straight line is 7 ms. It has a uniform acceleration of 4 ms2. The distance covered by the body in the 5th second of its motion is
A
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B
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C
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D
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Solution
The correct option is A Sn=u+a2[2n−1] S5th=7+42[2×5−1]=7+18=25m.