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Question

The initial velocity of a body moving on a rough horizontal surface having coefficient of friction 0.5 is 15 m/s. Find the time after which it will come to rest . [Take g = 10m/s2 ]

A
1.5 s
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B
3 s
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C
6 s
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D
7 s
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Solution

The correct option is B 3 s
Due to friction, the body face a retardation of a=μg [μ : coefficient of friction]
also u=15m/s and v=0 (as it comes to rest)
From kinematics,
v=u+at which means:
0=15μgtt=15mg=150.5×10=35 Ans

1068240_1167079_ans_894132e7ccdf4ca7b0f6327509459d95.png

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