Question

The initial velocity of a particle is 10 m/sec and its retardation is 2 m/$se{c}^2$. The distance moved by the particle in $5^{th}$ second of its motion is

• A. 1 m
• B. 19 m
• C. 50 m
• D. 75 m

Answer 1

The correct option is A

1 m

Using the formula for the distance travelled in the $n^{th}$ second

$S_n=u-\frac{a}{2}(2n-1)=10-\frac{2}{2}(2\times 5-1)=1$meter