The initial velocity of a particle- u-4i-3j- It is moving with uniform acceleration- a-0-4i-0-3j- Its velocity after 10 seconds is

The correct option is D 10 unitFinal velocity of x component, v_x=4+0.4× 10 = 8 Final velocity of y component #160; v_y=3+0.3× 10 = 6 Final velocit ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Vector Addition

The initial v...

Question

The initial velocity of a particle, $\to u = 4 \to i + 3 \to j$ . It is moving with uniform acceleration, $\to a = 0.4 \to i + 0.3 \to j$ . Its velocity after $10$ seconds is

3 unit

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 unit

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 unit

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 unit

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 10 unit
Final velocity of x-component, $v_{x} = 4 + 0.4 \times 10 = 8$
Final velocity of y-component $v_{y} = 3 + 0.3 \times 10 = 6$
Final velocity vector, $\to V = 8 i + 6 j$
Magnitude of velocity $= \sqrt{8^{2} + 6^{2}} = \sqrt{100} = 10 u n i t$

Suggest Corrections

Similar questions

Q. A particle has initial velocity

(2 \to i + 3 \to j)

and acceleration

(0.3 \to i + 0.2 \to j)

. The magnitude of velocity after 10 seconds will be

Q. A particle is moving with uniform acceleration, in eighth and thirteenth second after starting it moves through

255cm255cm respectively. Find its initial velocity and its acceleration

Q. A particle is moving with initial velocity

\to u = ˆ i - ˆ j + ˆ k

. What should be its acceleration so that it can remain moving in the same straight line?

Q. A particle is moving in a straight line with initial velocity and uniform acceleration

a

. If the sum of the distance travelled in

t^{t h}

and

{(t + 1)}^{t h}

seconds is

100 c m

, then its velocity after

t

seconds, in

c m / s

, is

Q. A particle moving with an initial velocity

^i - 4^j + 10^k

has acceleration

^i +^j - 2^k

. Its velocity at the end of 2 seconds, points along the unit vector:

Join BYJU'S Learning Program

The initial velocity of a particle, →u=4→i+3→j. It is moving with uniform acceleration, →a=0.4→i+0.3→j. Its velocity after 10 seconds is

The correct option is D 10 unitFinal velocity of x-component, vx=4+0.4×10=8Final velocity of y-component vy=3+0.3×10=6Final velocity vector, →V=8i+6jMagnitude of velocity =√82+62=√100=10 unit

The initial velocity of a particle, $\to u = 4 \to i + 3 \to j$ . It is moving with uniform acceleration, $\to a = 0.4 \to i + 0.3 \to j$ . Its velocity after $10$ seconds is

The correct option is D 10 unit
Final velocity of x-component, $v_{x} = 4 + 0.4 \times 10 = 8$
Final velocity of y-component $v_{y} = 3 + 0.3 \times 10 = 6$
Final velocity vector, $\to V = 8 i + 6 j$
Magnitude of velocity $= \sqrt{8^{2} + 6^{2}} = \sqrt{100} = 10 u n i t$