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Question

The initial velocity of the particle is 10 msec and its retardation is 2m/s2. The distance moved by the particle is 5th second of its motion is :

A
1m
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B
19m
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C
50m
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D
75m
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Solution

The correct option is A 1m
Given,
u=10m/s
a=2m/s2
n=5
The distance covered by the particle in nthsec
Sn=u+a2(2n1)
S5=10+22(2×51)
S5=109
S5=1m
The correct option is A.


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