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Question

The initial velocity of the particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is

A
1 m
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B
19 m
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C
50 m
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D
75 m
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Solution

The correct option is A 1 m
As we know that the distance travelled by a particle in nth second is given as
Sn=u+a2(2n1)
Given, u=10 m/s,a=2 m/s2
S5th=1022(2×51)=1 meter

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