The inlet and the outlet conditions of steam for an adiabatic steam turbine are as indicated in the notations are as usually followed.
If mass flow rate of steam through the turbine is 20 kg/s, the power output of the turbine (in MW) is
A
12.157
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12.941
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
168.001
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
168.785
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 12.157 Applying the steady flow energy equation, m(h1+V212+gz1)+Q=m(h2+V212+gz2)+W
where Q = 0 for adiabatic flow, m(h1+V212+gz1)=m(h2+V212+gz2)+W
On units balancing, we get m(h1+V212000+gz11000)=m(h2+V212000+gz21000)+W 20(3200(16)22000+9.81×101000)=20(2600+(100)22000+9.81×61000)+W 64257.96=52101.17+W
or W=12156.79kW =12.1568MW =12.157MW