The inner circumference of a circular track is $24 π$ m. The track is $2$ m wide from everywhere. The quantity of wire required to surround the path completely is _________.

80

No worries! We‘ve got your back. Try BYJU‘S free classes today!

81

No worries! We‘ve got your back. Try BYJU‘S free classes today!

82

No worries! We‘ve got your back. Try BYJU‘S free classes today!

88

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $88$ m
Circumference of the inner circle $= 2 π r = 24 π$ $=> r = 12$ m
Radius of the outer circle $= 14$ m
Therefore, circumference of the outer circle $= 2 π (14) = 2 \times 22 = 88 m$
(Assuming $π = \frac{22}{7}$ )

Suggest Corrections

Similar questions

Q. The inside circumference of a circular track is 440 m long and the track is 7 m wide everywhere. The area of the track is

Q. The inner circumference of a circular track is 330 m. The track is 10.5 m wide everywhere. Calculate the cost of putting up a fence along the outer circle at the rate of Rs 20 per metre.

Q. The inner circumference of a circular tracks is

220 m

. The track is

7

m

wide everywhere. Calculate the cost of putting up a fence along the outer circle at the rate of Rs.

2

per metre. Use

π = \frac{22}{7}

Q. The inner circumference of a circular track

14 m

wide is

440 m

. The radius of the outer circle is

The outer circumference of a circular race-track is $528 m$ . The track is everywhere $14 m$ wide. Calculate the cost of levelling the track at the rate of $50$ paise per square metre . Use $π = \frac{22}{7}$

Join BYJU'S Learning Program

The inner circumference of a circular track is 24πm. The track is 2m wide from everywhere. The quantity of wire required to surround the path completely is _________.

The correct option is D 88mCircumference of the inner circle=2πr=24π =>r=12mRadius of the outer circle =14mTherefore, circumference of the outer circle =2π(14)=2×22=88m(Assuming π=227)

The inner circumference of a circular track is $24 π$ m. The track is $2$ m wide from everywhere. The quantity of wire required to surround the path completely is _________.

The correct option is D $88$ m
Circumference of the inner circle $= 2 π r = 24 π$ $=> r = 12$ m
Radius of the outer circle $= 14$ m
Therefore, circumference of the outer circle $= 2 π (14) = 2 \times 22 = 88 m$
(Assuming $π = \frac{22}{7}$ )