Question

The inner diameter of a cylindrical wooden pipe is $24$cm and its outer diameter is $28$cm. The pipe is $35$cm long. Find the mass of the pipe if $1c{m}^3$ of wood has a mass of $0.6$gm.

Answer 1

Given

Inner diameter$=24cm$ , outer diameter$=28cm$ and Lenght of pipe$=35cm$

Volume of pipe $=\pi (R^2-r^2)\times h=\frac{22}{7}\times ({\left(14\right)}^2-{\left(12\right)}^2)\times 35$

$=100\times 52=5720{cm}^3$

Mass of the pipe is:

$1{cm}^3=0.6gm$.....Given

$\Rightarrow 5720{cm}^3=(0.6\times 5720)gm=3432gm$