Question

The inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28 cm. The length of the pipe is 35cm.Find the mass of the pipe, if 1cm³ of wood has a mass of 0.6g.

Answer 1

Inner radius of cylindrical pipe, say r₁ = $\frac{diamete{r}_1}{2}=\frac{24}{2}cm=12cm$
Outer radius of cylindrical pipe, say $r_2=\frac{diamete{r}_2}{2}=\frac{28}{2}cm=14cm$
Height of pipe, h = Length of pipe = 35cm
Now, the Volume of pipe = π (r₂² - r₁²) h cm³
Substitute the values.
Volume of pipe = $\frac{22}{7}\times ({14}^2-{12}^2)\times 35$
=110 × 52
= 5720 cm³
Since, Mass of 1 cm³ wood = 0.6 g
Mass of 5720 cm³ wood = (5720 × 0.6) g
= 3432 g or 3.432 kg.