The inner diameter of a metallic tube of density $7 g / c m^{3}$ is $2.5 c m$ . The thickness of the tube is $0.29 c m$ . Find the weight of the tube, if it is of length $30 c m$ .

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Solution

Inner diameter $= 2.5 ㎝$
Inner radius $= 2.5 / 2 = 1.25 ㎝$
Thickness $= 0.29 ㎝$
Outer radius $= 1.25 + 0.29 = 1.54 ㎝$
Volume of tube $= π (R^{2} - r^{2}) \times h$
$= \frac{22}{7} ({1.54}^{2} - {(1.25)}^{2}) \times 30$
$= 76.30 ㎤$
Weight of tube $= 76.30 \times 7 = 534.10 ℊ$

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The inner diameter of a metallic tube of density 7 g/cm3 is 2.5 cm. The thickness of the tube is 0.29 cm. Find the weight of the tube, if it is of length 30 cm.

Inner diameter=2.5㎝Inner radius=2.5/2=1.25㎝Thickness=0.29㎝Outer radius=1.25+0.29=1.54㎝Volume of tube=π(R2−r2)×h=227(1.542−(1.25)2)×30=76.30㎤Weight of tube=76.30×7=534.10ℊ

The inner diameter of a metallic tube of density $7 g / c m^{3}$ is $2.5 c m$ . The thickness of the tube is $0.29 c m$ . Find the weight of the tube, if it is of length $30 c m$ .

Inner diameter $= 2.5 ㎝$
Inner radius $= 2.5 / 2 = 1.25 ㎝$
Thickness $= 0.29 ㎝$
Outer radius $= 1.25 + 0.29 = 1.54 ㎝$
Volume of tube $= π (R^{2} - r^{2}) \times h$
$= \frac{22}{7} ({1.54}^{2} - {(1.25)}^{2}) \times 30$
$= 76.30 ㎤$
Weight of tube $= 76.30 \times 7 = 534.10 ℊ$