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Question

The inner radius of a hollow iron sphere is 9cm. If iron is 1cm thick, find the volume of iron used to make the ball.


A

1155.08 cm3

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B

1156.08 cm3

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C

1134.59 cm3

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D

1133.58 cm3

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Solution

The correct option is C

1134.59 cm3


Thickness of the iron = 1cm
Inner radius = 9cm
Therefore, inner volume of sphere = 43 π (rinner)3
=43 × π × (9)3
=3052.08cm3
Outer radius = 10cm
Outer volume = 43 ×π × (router)3
=43 π (10)3
=4186.67cm3
Then, iron used = Outer volume - Inner volume
=1134.59 cm3


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