The input-output transfer function of a plant $H (s) = \frac{100}{s (s + 10)^{2}}$ , The plant is placed in a unity negative feedback configuration as shown in the figure below.

The signal flow graph that DOES NOT model the plant transfer function $H (s)$ is

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Solution

The correct option is D
For option (d),
$\frac{Y (s)}{U (s)} = \frac{100 / s^{3}}{1 + \frac{100}{s^{2}}}$
Which is not transfer function of $H (s)$ .

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The input-output transfer function of a plant H(s)=100s(s+10)2, The plant is placed in a unity negative feedback configuration as shown in the figure below. The signal flow graph that DOES NOT model the plant transfer function H(s) is

The correct option is D For option (d), Y(s)U(s)=100/s31+100s2 Which is not transfer function of H(s).

The input-output transfer function of a plant $H (s) = \frac{100}{s (s + 10)^{2}}$ , The plant is placed in a unity negative feedback configuration as shown in the figure below.

The signal flow graph that DOES NOT model the plant transfer function $H (s)$ is

The correct option is D
For option (d),
$\frac{Y (s)}{U (s)} = \frac{100 / s^{3}}{1 + \frac{100}{s^{2}}}$
Which is not transfer function of $H (s)$ .