Question

The input resistance of a common-emitter amplifire is $2k\Omega$ and $a.c.$ current gain in $20$. If the load resistor used is $5k\Omega$, calculate the trans conductance of the transistor used:

• A. $0.01{\Omega }^{-1}$
• B. $0.03{\Omega }^{-1}$
• C. $0.04{\Omega }^{-1}$
• D. $0.07{\Omega }^{-1}$

Answer 1

The correct option is A $0.01{\Omega }^{-1}$

AC current gain, Be = 20 and Input resistance $=2k\Omega$

$\therefore$ Transconduetance, gm $=\frac{Bc}{Rinp}=\frac{20}{2\times {10}^3}=0.01{\Omega }^{-1}$