Question

The input voltage from inverter is controlled by a single pulse modulation technique. The output voltage is free from $5^{th}$ harmonic. If supply voltage is 200 V dc, then the maximum peak value of fundamental component is _____ V(Answer up to 2 decimal places).

• A. 242.18

Answer 1

The correct option is A 242.18
$V_0=\sum _{1,3,5,...}^{\infty }\frac{4V_s}{n\pi }\sin \frac{n\pi }{2}.\sin nd.\sin n\omega t$

$V_{01(max)}=\frac{4V_s}{\pi }\sin \frac{\pi }{2}\sin d$

Since, the output voltage is free from $5^{th}$ harmonic

$2d=\frac{2\pi }{5},\frac{4\pi }{5}$

$d={36}^o,{72}^o$

Maximum peak value of fundamental component is obtained for $d={72}^o$

$V_{01(max)}=\frac{4\times 200}{\pi }\times 1\times \sin {72}^0$

$V_{01(max)}=242.18V$