The input X to the Binary Symmetric Channel (BSC) shown in the figure '1' with probability 0.8.
The crossover probability is 1/7. If the received bit Y = 0,. the conditional probability that '1' was transmitted is
Let y = {Received bit is y = 0}
E1={Input x = 0}, E2={Input X = 1}
P(E1)=P(X=0)=0.2,
& P(E2)=P(X=1)=0.8
P(Y/E2)=P[Y=0X=1]=17
P(Y/E1)=P[Y=0X=0]=67
So by Baye's theorem
P[X=1Y=0]=P(E2Y)
=P(E2).P(Y/E2)P(E1).P(Y/E1)+P(E2).P(Y/E2)
=0.8×170.2×67+0.8×17=0.4