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Question

The inputs to the digital circuit are shown below. The output Y is.

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A
A+B+¯C
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B
(A+B)¯C
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C
¯A+¯B+¯C
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D
¯A+¯B+C
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Solution

The correct option is C ¯A+¯B+¯C
A and B are inputs to the NAND gate. The output of that gate is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A.B)=¯¯¯¯A+¯¯¯¯B.
The output of C being input to the NOT gate is ¯¯¯¯C.
These two are inputs of OR gate.
Hence Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A.B)+¯¯¯¯C
=¯¯¯¯A+¯¯¯¯B+¯¯¯¯C

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