The inradius of an equilateral triangle of side $6 \sqrt{3}$

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2 \sqrt{3}

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3 \sqrt{3}

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4 \sqrt{3}

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Solution

The correct option is A 3
The inradius of a triangle is given by:
r =
Here a = 6√3 is the side of the triangle.
Hence, the answer is 3 units

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