Radial & Tangential Acceleration for Non Uniform Circular Motion
The instantan...
Question
The instantaneous angular position of a particle undergoing a circular motion is given by the equation θ(t)=4t3−3t2. Find the time when the angular acceleration of the particle becomes zero.
A
0.50s
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B
0.25s
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C
1s
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D
2s
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Solution
The correct option is B0.25s As we know that the angular acceleration of the particle is given by α=d2θdt2
We have, dθdt=d(4t3−3t2)dt=12t2−6t
also, d2θdt2=d(12t2−6t)dt2=24t−6
Thus, the time when α will be zero is given as 24t−6=0⇒t=624=0.25s