The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=3t3−9t2 (Here t is in seconds). The angular acceleration of the wheel becomes zero at
A
t=1s
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B
t=0.5s
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C
t=0.25s
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D
t=2s
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Solution
The correct option is At=1s We know that angular velocity is the rate of change of angular position of a rotating body and angular acceleration refers to the rate of change of angular velocity
It is given that θ(t)=3t3−9t2
hence, ω=dθdt=9t2−18t α=d2θdt2=dωdt=18t−18
It is said that angular acceleration becomes 0, hence α=18t−18=0 t=1s