The instantaneous angular position of a point on a rotating wheel is given by the equation -t-2 t3-6 t2The torque on the wheel becomes zero at-

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Centripetal Acceleration

The instantan...

Question

The instantaneous angular position of a point on a rotating wheel is given by the equation

Θ(t) = 2t³ – 6t²

The torque on the wheel becomes zero at:

t=1 s

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t=2s

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t=0.5s

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t=0.25s

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Solution

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Similar questions

θ (t) = 2 t^{3} - 6 t^{2}

θ (t) = 2 t^{3} - 6 t^{2}

θ (t) = 3 t^{3} - 9 t^{2}

t

θ (t) = 3 t^{3} - 9 t^{2}

t

(I = 2 {kg-m}^{2})

ω (t) = (2 t^{2} + 4) rad/s

t = 2 s

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