Question

The instantaneous current from an a.c source is $I=5\sin 314t$. What is the (i) peak value (ii) r.m.s. value (iii) frequency of current?

Answer 1

$I=5sin\left(314t\right)$

( 1 ) peak value

$I_0=5A$

( 2 ) R.M.S value

$I_{rms}=\frac{I_0}{\sqrt{2}}=\frac{5}{\sqrt{2}}$

= $3.53A$

( 3 ) $T$ = $\frac{2\pi }{w}=\frac{2\pi }{314}$

frequcey = $\frac{1}{T}=\frac{314}{2\pi }$

= $50HZ$