The instantaneous oscillating electric field of EM wave is E0^j and magnetic field is oscillating along -ve (^k) direction having magnitude B0, then velocity of EM wave is
A
E0B0^i
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B
−E0B0^i
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C
−E0B0^i
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D
−E0B0^k
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Solution
The correct option is C−E0B0^i Given, direction of electric field= E0^j and oscillation of magnetic field= −B0^k Direction of proportion =^E×^B =^j×(−^k)=−^i And, magnitude (V)=EB Hence, −E0B0^i