The instantaneous values of current and emf in an ac circuit are I-1-2 sin 314tamp and E - -2 sin314t -6V respectively- The phase difference between E and I will be

Phase difference relative to the current ϕ=(314t π/6) (314t)= π/6 ...

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Impedance Triangle

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Question

The instantaneous values of current and emf in an ac circuit are $I = \frac{1}{\sqrt{2}} s i n$ 314tamp and $E = \sqrt{2} s i n (314 t - \frac{Π}{6})$ V respectively. The phase difference between E and I will be

\frac{- Π}{6 r a d}

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\frac{- Π}{3 r a d}

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\frac{Π}{6 r a d}

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\frac{Π}{3 r a d}

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I = \frac{1}{\sqrt{2}} s i n

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

e = 200 sin 314 t

I = sin (314 t + \frac{π}{3})

= 200 sin (ω t - \frac{π}{3});

= 10 sin (ω t + \frac{π}{6})

e = E_{0} sin (ω t - π / 6), i = I_{0} sin (ω t + π / 6)

i = s i n (314 t + \frac{π}{3})

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