The instantaneous velocity of a point on the outer edge of a disk with a diameter of 4 m that is rotating at 120 revolutions per minute is most nearly:
A
4 m/s
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B
6 m/s
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C
12 m/s
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D
25 m/s
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E
50 m/s
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Solution
The correct option is D 25 m/s Radius of the disk r=d2=42=2 m
Frequency of rotation f=120 rpm =12060=2 rps
Thus instantaneous linear velocity v=rw=r(2πf)=2×(2π×2)≈25 m/s