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Question

The integer k for which the inequality x22(4k1)x+15k22k7>0 is valid for any x is :

A
2
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B
1
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C
4
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D
6
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Solution

The correct option is B 1
Let f(x)=x22(4k1)x+15k22k7. Then
f(x)>0D<0[Coefficient of x2>0]
4(4k1)24(15k22k7)<0
k26k+8<02<k<4

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