The integers P,Q,R and S shown on the number line below are all equally spaced. If R and S are equal to 712 and 713, respectively, what is the value of P?
The distance between R and S is 713−712=6×712
The distance between two consecutive points is constant.
Value of Q=712−6×712=−5×712
Value of P=−5×712−6×712=−11×712
The correct answer is option (d).