The integral -1-2-1-2-x-log1-x1-xdx to equals- where - denotes greatest integer function

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Definite Integral as Limit of Sum

The integral ...

Question

The integral $\int_{- 1 / 2}^{1 / 2} ([x] + log (\frac{1 + x}{1 - x})) d x$ to equals, where $[.]$ denotes greatest integer function

- \frac{1}{2}

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log (\frac{1}{2})

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Similar questions

1 / 2 \int - 1 / 2 {[x] + log (\frac{1 + x}{1 - x})} d x

(

[\cdot]

)

\int_{- 1 / 2}^{1 / 2} ([x] + log \frac{1 + x}{1 - x}) d x

2 \int - 2 ([x] + log (\frac{1 + x}{1 - x}) + sin (log (\frac{2 + x}{2 - x})) + x^{2011}) d x

2 \int - 1 [\frac{[x]}{1 + x^{2}}] d x,

[\cdot]

\int_{0} [x] x d x = \int_{0} x [x] d x

[.]

x

\int_{1}^{2} x d x

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