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Question

The integral dx(1+sinx)1/2 is equal to

A
2log|cot3π8x4|+c
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B
2log|cosec(π4+x2)cot(π4+x2)|+c
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C
2log|tan(π8+x4)|+c
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D
2log|sec(π4x2)+tan(π4x2)|+c
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Solution

The correct options are
A 2log|cot3π8x4|+c
B 2log|tan(π8+x4)|+c
C 2log|sec(π4x2)+tan(π4x2)|+c
D 2log|cosec(π4+x2)cot(π4+x2)|+c
Given dx(1+sinx)1/2
dx(cos(x/2)+sin(x/2))2×(1/2)
dx((1/2)cos(x/2)+(1/2)sin(x/2))(2)
dx(sin(π/4)cos(x/2)+(cos(π/4)sin(x/2))(2)
dx(sin((π/4)+(x/2))(2)
12cosec((x/2)+(π/4))dx
Since cosec(x)dx=log|cosec(x)cot(x)|
Hence (2)log|cosec((x/2)+(π/4))cot((x/2)+(π/4))|+c ie option B is the answer.

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