The integral - 1-2 x 2 - 1 - x e x 2- 1 - x dx is equal to

The correct option is C xe^x^2 1x+c [ Let; I=∫ e^ x^ 2 1 / x #160; ( 1+2 x^ 2 ...

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Combination

The integral ...

Question

The integral $\int (1 + 2 x^{2} + \frac{1}{x}) e^{x^{2 - \frac{1}{x}}} d x$ is equal to

(2 x - 1) . e^{x^{2 - \frac{1}{x}}} + c

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(2 x + 1) . e^{x^{2 - \frac{1}{x}}} + c

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x e^{x^{2 - \frac{1}{x}}} + c

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- x e^{x^{2 - \frac{1}{x}}} + c

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