wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The integral 1+2cotx(cosec x+cotx)dx (0<x<π2) is equal to. (where C is a constant of integration).

A
2log(cosx2)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4log(sinx2)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4log(cosx2)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2log(sinx2)+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2log(sinx2)+C
(2cotx cosec x+cosec2x+cot2x)dx

|cosec x+cotx|dx

(cosec x+cotx)dx

1+cosxsinxdx

cotx2dx

2log(sinx2)+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon